JEE MAIN - Chemistry (2014 (Offline) - No. 5)
For the reaction SO2 (g) + $${1 \over 2} O_2(g) \leftrightharpoons$$ SO3(g).
if KP = KC(RT)x where the symbols have usual meaning then the value of x is: (assuming ideality)
if KP = KC(RT)x where the symbols have usual meaning then the value of x is: (assuming ideality)
-1
-1/2
1/2
1
설명
$$S{O_2}\left( g \right) + {1 \over 2}{O_2}\left( g \right)\,\rightleftharpoons\,S{O_3}\left( g \right)$$
$${K_p} = {K_C}{\left( {RT} \right)^x}$$
where $$x = \Delta {n_g} = $$ number of gaseous moles in product
$$\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,$$$$-$$ number of gaseous moles in reactant
$$ = 1 - \left( {1 + {1 \over 2}} \right)$$
$$ = 1 - {3 \over 2} = - {1 \over 2}$$
$${K_p} = {K_C}{\left( {RT} \right)^x}$$
where $$x = \Delta {n_g} = $$ number of gaseous moles in product
$$\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,$$$$-$$ number of gaseous moles in reactant
$$ = 1 - \left( {1 + {1 \over 2}} \right)$$
$$ = 1 - {3 \over 2} = - {1 \over 2}$$